(x^2+4x+4)/(12x-4-9x^2)=0

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Solution for (x^2+4x+4)/(12x-4-9x^2)=0 equation: 



(x^2+4x+4)/(12x-4-9x^2)=0



Domain of the equation: (12x-4-9x^2)!=0

We move all terms containing x to the left, all other terms to the right

-9x^2+12x!=4

x∈R



We multiply all the terms by the denominator


(x^2+4x+4)=0

We get rid of parentheses

x^2+4x+4=0

a = 1; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{2}=-2$

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